Soalan daripada kawan saya:
Solution:
Question (a)
We know that total number of students is 35 but n(A∪B∪C) ≠ 35.
Solution:
Question (a)
We know that total number of students is 35 but n(A∪B∪C) ≠ 35.
There are three students who did not choose any subject.
So, we have n(A∪B∪C)' = 3. Then
From the first three rows, we know that
The forth, fifth and sixth rows have word "and" which means "intersection" represents by this symbol ∩. From the information, we know thatSo, we have n(A∪B∪C)' = 3. Then
n(A∪B∪C) = 35-3 =32
n(A∩B) = 10, n(B∩C) = 11 and n(A∩C) = 9
Question (b)
n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C)
- n(A∩C) + n(A∩B∩C)
aaaaaaaa32 = 17 + 15 + 21- 9 - 11 - 10 + n(A∩B∩C)
n(A∩B∩C) = 9
There are nine students who chose all three subjects.
Question (c)
No. of students chose who Anthropology only
= [n(A∩B) - n(A∩B∩C)]
+ [n(B∩C) - n(A∩B∩C)]
+ [n(A∩C) - n(A∩B∩C)]
= (10 - 9) + (11 - 9) + (9 - 9)
= 1 + 2 + 0
= 3
Question (b)
Number of students who chose all three subjects = n(A∩B∩C).
n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C)
- n(A∩C) + n(A∩B∩C)
aaaaaaaa32 = 17 + 15 + 21- 9 - 11 - 10 + n(A∩B∩C)
n(A∩B∩C) = 9
There are nine students who chose all three subjects.
Question (c)
No. of students chose who Anthropology only
= n(A)
- n(A∩B) - n(A∩C)
+ n(A∩B∩C)
+ n(A∩B∩C)
= 17 - 9
- 10 + 9
= 7
Question (d)
No. of students who have two favorite subjects = [n(A∩B) - n(A∩B∩C)]
+ [n(B∩C) - n(A∩B∩C)]
+ [n(A∩C) - n(A∩B∩C)]
= (10 - 9) + (11 - 9) + (9 - 9)
= 1 + 2 + 0
= 3
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