Question:
If f (x) = 3x² + 2x +1, find the first derivative of f at x = 0.
Answers:
1st version:
f '(x) = 6x + 2 = 6(0) + 2 = 2
2nd version:
f '(x) = 6x + 2
f '(0) = 6(0) + 2 = 2
The truth f '(x) ≠ 2 but f '(0) = 2.
If f (x) = 3x² + 2x +1, find the first derivative of f at x = 0.
Answers:
1st version:
f '(x) = 6x + 2 = 6(0) + 2 = 2
2nd version:
f '(x) = 6x + 2
f '(0) = 6(0) + 2 = 2
The truth f '(x) ≠ 2 but f '(0) = 2.
