Question Answer - 1



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Soalan daripada kawan saya:

Solution:

Question (a)
We know that total number of students is 35 but n(A∪B∪C)  35.
There are three students who did not choose any subject. 
So, we have n(A∪B∪C)' = 3. Then
n(A∪B∪C) = 35-3 =32

From the first three rows, we know that 
n(A) = 17, n(B) = 15 and n(C) = 21



The forth, fifth and sixth rows have word "and" which means "intersection" represents by this symbol ∩. From the information, we know that
n(AB) = 10, n(BC) = 11 and n(AC) = 9



Question (b)
Number of students who chose all three subjects = n(A∩B∩C). 

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C)
                       - n(A∩C) + n(A∩B∩C)
aaaaaaaa32 = 17 + 15 + 21- 9 - 11 - 10 + n(A∩B∩C)
n(A∩B∩C) = 9

There are nine students who chose all three subjects.

Question (c)
No. of students chose who Anthropology only 

= n(A) - n(A∩B) - n(A∩C) 
   + n(A∩B∩C)
= 17 - 9 - 10 + 9
= 7



Question (d)
No. of students who have two favorite subjects 
= [n(A∩B) - n(A∩B∩C)] 
     + [n(B∩C) - n(A∩B∩C)] 
     + [n(A∩C) - n(A∩B∩C)]
= (10 - 9) + (11 - 9) + (9 - 9)
= 1 + 2 + 0 
= 3

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